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	<title>Comments on: Constructive gem: irrational to the power of irrational that is rational</title>
	<atom:link href="http://math.andrej.com/2009/12/28/constructive-gem-irrational-to-the-power-of-irrational-that-is-rational/feed/" rel="self" type="application/rss+xml" />
	<link>http://math.andrej.com/2009/12/28/constructive-gem-irrational-to-the-power-of-irrational-that-is-rational/</link>
	<description>Mathematics for computers</description>
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		<title>By: Andrej Bauer</title>
		<link>http://math.andrej.com/2009/12/28/constructive-gem-irrational-to-the-power-of-irrational-that-is-rational/comment-page-1/#comment-18247</link>
		<dc:creator>Andrej Bauer</dc:creator>
		<pubDate>Sat, 10 Dec 2011 10:08:20 +0000</pubDate>
		<guid isPermaLink="false">http://math.andrej.com/?p=410#comment-18247</guid>
		<description>@Terry: Hmm, actually I do not know what you mean if you have in mind the usual non-constructive proof involving $\sqrt{2}^\sqrt{2}$, because that number is transcedental, as it is the square root of the &lt;a href=&quot;http://en.wikipedia.org/wiki/Gelfond%E2%80%93Schneider_constant&quot; rel=&quot;nofollow&quot;&gt;Gelfand-Schneider Constant&lt;/a&gt;.</description>
		<content:encoded><![CDATA[<p>@Terry: Hmm, actually I do not know what you mean if you have in mind the usual non-constructive proof involving $\sqrt{2}^\sqrt{2}$, because that number is transcedental, as it is the square root of the <a href="http://en.wikipedia.org/wiki/Gelfond%E2%80%93Schneider_constant" rel="nofollow">Gelfand-Schneider Constant</a>.</p>
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		<title>By: Andrej Bauer</title>
		<link>http://math.andrej.com/2009/12/28/constructive-gem-irrational-to-the-power-of-irrational-that-is-rational/comment-page-1/#comment-18245</link>
		<dc:creator>Andrej Bauer</dc:creator>
		<pubDate>Sat, 10 Dec 2011 08:34:08 +0000</pubDate>
		<guid isPermaLink="false">http://math.andrej.com/?p=410#comment-18245</guid>
		<description>@Terry: That&#039;s a good point. Can we have a constructive proof of two irrational algebraic numbers whose power is rational?</description>
		<content:encoded><![CDATA[<p>@Terry: That&#8217;s a good point. Can we have a constructive proof of two irrational algebraic numbers whose power is rational?</p>
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		<title>By: Terry</title>
		<link>http://math.andrej.com/2009/12/28/constructive-gem-irrational-to-the-power-of-irrational-that-is-rational/comment-page-1/#comment-18243</link>
		<dc:creator>Terry</dc:creator>
		<pubDate>Sat, 10 Dec 2011 01:40:56 +0000</pubDate>
		<guid isPermaLink="false">http://math.andrej.com/?p=410#comment-18243</guid>
		<description>Note though that the non-constructive argument proves something stronger than the constructive one, namely that there exist two irrational &lt;i&gt;algebraic&lt;/i&gt; numbers $a$, $b$ such that $a^b$ is rational.</description>
		<content:encoded><![CDATA[<p>Note though that the non-constructive argument proves something stronger than the constructive one, namely that there exist two irrational <i>algebraic</i> numbers $a$, $b$ such that $a^b$ is rational.</p>
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		<title>By: Cody Roux</title>
		<link>http://math.andrej.com/2009/12/28/constructive-gem-irrational-to-the-power-of-irrational-that-is-rational/comment-page-1/#comment-13550</link>
		<dc:creator>Cody Roux</dc:creator>
		<pubDate>Mon, 05 Jul 2010 11:56:01 +0000</pubDate>
		<guid isPermaLink="false">http://math.andrej.com/?p=410#comment-13550</guid>
		<description>I see the proof of the above theorem in a somewhat different way than &quot;a useless example of non-constructive proof&quot;. Let me make my point using a Car Analogy. You go to a car dealer, and he supplies a car to you, along with a guarantee: He must supply a -working- car to you, if needed. If you never use the car, the contract is implicitly satisfied, otherwise, if you do try to start the car, then two cases may occur: The car starts, and everything is fine, or the car does not start. In this case, you make use of your guarantee, and the dealer supplies a new, working car (or some other car with another guarantee). You do the same for your classical proof of existence of 2 irrational numbers $a$ and $b$ such that $a^b$ is rational: act as if $a=\sqrt{2}$ and $b=\sqrt{2}$ satisfy your theorem. If anyone calls you out on it, by supplying a proof that $\sqrt{2}^\sqrt{2}$ is irrational, you can &quot;backtrack&quot; by supplying new witnesses to your theorem: $a=\sqrt{2}^\sqrt{2}$ and $b=\sqrt{2}$. In a sense, the non-constructive proof does contain &quot;less information&quot; than the constructive proof. However it does supply a &quot;guarantee&quot; as in the above sense, that is you may use your witnesses with the caveat of perhaps needing to substitute them for &quot;correct&quot; witnesses at a further point.</description>
		<content:encoded><![CDATA[<p>I see the proof of the above theorem in a somewhat different way than &#8220;a useless example of non-constructive proof&#8221;. Let me make my point using a Car Analogy. You go to a car dealer, and he supplies a car to you, along with a guarantee: He must supply a -working- car to you, if needed. If you never use the car, the contract is implicitly satisfied, otherwise, if you do try to start the car, then two cases may occur: The car starts, and everything is fine, or the car does not start. In this case, you make use of your guarantee, and the dealer supplies a new, working car (or some other car with another guarantee). You do the same for your classical proof of existence of 2 irrational numbers $a$ and $b$ such that $a^b$ is rational: act as if $a=\sqrt{2}$ and $b=\sqrt{2}$ satisfy your theorem. If anyone calls you out on it, by supplying a proof that $\sqrt{2}^\sqrt{2}$ is irrational, you can &#8220;backtrack&#8221; by supplying new witnesses to your theorem: $a=\sqrt{2}^\sqrt{2}$ and $b=\sqrt{2}$. In a sense, the non-constructive proof does contain &#8220;less information&#8221; than the constructive proof. However it does supply a &#8220;guarantee&#8221; as in the above sense, that is you may use your witnesses with the caveat of perhaps needing to substitute them for &#8220;correct&#8221; witnesses at a further point.</p>
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		<title>By: Ananymous</title>
		<link>http://math.andrej.com/2009/12/28/constructive-gem-irrational-to-the-power-of-irrational-that-is-rational/comment-page-1/#comment-13285</link>
		<dc:creator>Ananymous</dc:creator>
		<pubDate>Thu, 11 Mar 2010 19:47:27 +0000</pubDate>
		<guid isPermaLink="false">http://math.andrej.com/?p=410#comment-13285</guid>
		<description>An intuitionist logic professor told me that once he was trying to solve a problem from his own book preparing for the next day&#039;s undergrad logic lecture. After hours of unsuccessful thinking he noticed that he was not able to solve it because he was not using PEM. :)</description>
		<content:encoded><![CDATA[<p>An intuitionist logic professor told me that once he was trying to solve a problem from his own book preparing for the next day&#8217;s undergrad logic lecture. After hours of unsuccessful thinking he noticed that he was not able to solve it because he was not using PEM. :)</p>
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